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ATP Luan II 2025 predictions

ATP Luan II 2025 predictions / China, kemény , ATP Luan II 2025 Tenisz élő
borítás: 15 000 USD
Apr 20, 2025
04:11
döntő Sornlaksup Pawit (THA) (768) 49.56% 2 6 6 1.73 I H2H O AI
Peliwo Filip (POL) [3] (589) 50.44% 0 1 3 2
Apr 19, 2025
04:11
elődöntő Sornlaksup Pawit (THA) (768) 55.39% 2 6 6 1.14 I H2H O AI
Kim Geun Jun (KOR) [Q] (1820) 44.61% 0 0 3 4.84
Apr 19, 2025
04:11
elődöntő Peliwo Filip (POL) [3] (589) 35.42% 2 6 7 2.91 I H2H O AI
Te Rigele (CHN) [1] (531) 64.58% 0 3 6 (8) 1.34
Apr 18, 2025
05:22
negyeddöntő Sornlaksup Pawit (THA) (768) 64.23% 2 6 6 1.31 I H2H O AI
Sarksian Daniil (RUS) (1151) 35.77% 0 1 0 2.97
Apr 18, 2025
04:11
negyeddöntő Peliwo Filip (POL) [3] (589) 65.59% 1 6 1 1.61 I H2H O AI
Xiao Linang (CHN) (727) 34.41% 0 2 0 2.2
Apr 18, 2025
06:30
negyeddöntő Kim Geun Jun (KOR) [Q] (1820) 45.96% 1 5.5 I H2H O AI
Zhang Tianhui (CHN) (717) 54.04% 0 1.12
Apr 18, 2025
04:11
negyeddöntő Te Rigele (CHN) [1] (531) 2 6 6 1.23 I H2H O AI
Lee Kuan-Yi (TAI) (859) 0 2 2 3.55
Apr 17, 2025
06:27
nyolcaddöntő Zhang Tianhui (CHN) (717) 64.58% 2 6 6 1.78 I H2H O AI
Benchetrit Elliot (MAR) [5] (613) 35.42% 0 3 4 1.9
Apr 17, 2025
06:16
nyolcaddöntő Te Rigele (CHN) [1] (531) 68.42% 2 6 6 7 1.05 I H2H O AI
Dong Zhenxiong (CHN) [WC] (999) 31.58% 1 7 (4) 2 5 7.16
Apr 17, 2025
04:00
nyolcaddöntő Lee Kuan-Yi (TAI) (859) 2 7 6 I H2H O AI
Crowther Corban (NZL) [Q] (1021) 0 6 (4) 1
Apr 17, 2025
05:30
nyolcaddöntő Peliwo Filip (POL) [3] (589) 2 6 6 I H2H O AI
Lu Pengyu (CHN) [WC] (941) 0 1 3
Apr 17, 2025
04:15
nyolcaddöntő Xiao Linang (CHN) (727) 65.98% 2 6 7 1.31 I H2H O AI
Chen Charles (CHN) [WC] (1125) 34.02% 0 2 6 (2) 2.97
Apr 17, 2025
04:15
nyolcaddöntő Sornlaksup Pawit (THA) (768) 71.72% 2 6 6 1.16 I H2H O AI
Liu Hanyi (CHN) [LL] (1242) 28.28% 0 1 2 4.31
Apr 17, 2025
05:30
nyolcaddöntő Kim Geun Jun (KOR) [Q] (1820) 42.61% 2 7 2 6 4.64 I H2H O AI
Mo Ye Cong (CHN) [2] (547) 57.39% 1 6 (1) 6 3 1.14
Apr 17, 2025
04:00
nyolcaddöntő Sarksian Daniil (RUS) (1151) 37.96% 2 7 6 2.88 I H2H O AI
Chanta Thanapet (THA) [8] (671) 62.04% 0 5 2 1.33
Apr 16, 2025
09:25
1. kör Kim Geun Jun (KOR) [Q] (1820) 45.73% 1 7 2 2.69 I H2H O AI
Jiang Fumin (CHN) 54.27% 0 6 (7) 2 1.37
Apr 16, 2025
04:00
1. kör Chen Charles (CHN) [WC] (1125) 30.34% 2 3 7 6 3.01 I H2H O AI
Leong Mitsuki Wei Kang (MYS) [6] (617) 69.66% 1 6 6 (0) 2 1.3
Apr 16, 2025
08:05
1. kör Sornlaksup Pawit (THA) (768) 60.58% 2 6 6 6 1.59 I H2H O AI
Zhu Evan (USA) [4] (616) 39.42% 1 1 7 (5) 3 2.17
Apr 16, 2025
08:50
1. kör Te Rigele (CHN) [1] (531) 62.21% 2 6 7 1.04 I H2H O AI
You Du (CHN) [Q] 37.79% 0 4 6 (3) 7.63
Apr 16, 2025
04:00
1. kör Dong Zhenxiong (CHN) [WC] (999) 2 6 7 I H2H O AI
Zgirovsky Alexander (BLR) [Q] (1290) 0 3 5
Apr 16, 2025
07:04
1. kör Crowther Corban (NZL) [Q] (1021) 38.30% 2 2 6 6 1.96 I H2H O AI
Trongcharoenchaikul Wishaya (THA) (714) 61.70% 1 6 3 4 1.73
Apr 16, 2025
07:04
1. kör Peliwo Filip (POL) [3] (589) 68.48% 2 6 6 1.31 I H2H O AI
Zeng Yaojie (CHN) [Q] (1092) 31.52% 0 4 2 2.97
Apr 16, 2025
06:43
1. kör Liu Hanyi (CHN) [LL] (1242) 45.95% 2 6 3 6 2.12 I H2H O AI
Lomakin Grigoriy (KAZ) (838) 54.05% 1 4 6 2 1.62
Apr 16, 2025
04:00
1. kör Zhang Tianhui (CHN) (717) 63.77% 2 6 6 1.3 I H2H O AI
Efstathiou Menelaos (CYP) [Q] (983) 36.23% 0 3 2 3.02
Apr 16, 2025
04:00
1. kör Xiao Linang (CHN) (727) 34.81% 2 6 6 6 3.35 I H2H O AI
Santillan Akira (AUS) [Q] (734) 65.19% 1 7 (5) 4 3 1.25
Apr 16, 2025
06:10
1. kör Lu Pengyu (CHN) [WC] (941) 2 6 7 I H2H O AI
Liu Shaoyun (CHN) [Q] (1957) 0 2 6 (9)
Apr 15, 2025
07:15
1. kör Mo Ye Cong (CHN) [2] (547) 70.24% 2 6 3 6 I H2H O AI
Sinclair Colin (MNP) (684) 29.76% 1 4 6 4
Apr 15, 2025
05:35
1. kör Benchetrit Elliot (MAR) [5] (613) 55.70% 2 6 6 1.23 I H2H O AI
Tang Sheng (CHN) (898) 44.30% 0 3 3 3.49
Apr 15, 2025
05:42
1. kör Sarksian Daniil (RUS) (1151) 43.56% 2 6 6 2.12 I H2H O AI
Masabayashi Tomohiro (JPN) (724) 56.44% 0 3 4 1.62
Apr 15, 2025
05:55
1. kör Chanta Thanapet (THA) [8] (671) 61.08% 2 6 6 1.05 I H2H O AI
Sun Zhengyu (CHN) [WC] (1871) 38.92% 0 3 3 7.25
Apr 15, 2025
05:15
1. kör Lee Kuan-Yi (TAI) (859) 2 6 6 I H2H O AI
Brumm Jacob (USA) [7] (664) 0 4 0