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| ATP Winnipeg 2017 predictions / Canada, kemény , ATP Winnipeg 2017 Tenisz élő selejtető |
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| Jul 10, 2017 21:25 |
negyeddöntő | Bambridge Luke (GBR) (602) | 64.95% | 2 | 6 | 6 | 6 | I H2H O AI | |||
| Farren Connor (USA) (860) | 35.05% | 1 | 7 (6) | 4 | 4 | ||||||
| Jul 10, 2017 18:35 |
negyeddöntő | Martinez Luis David (VEN) (1046) | 56.41% | 2 | 1 | 7 | 7 | I H2H O AI | |||
| Peck Joshua (CAN) (1534) | 43.59% | 1 | 6 | 6 (5) | 6 (4) | ||||||
| Jul 10, 2017 17:05 |
negyeddöntő | Schneider Ronnie (USA) (1786) | 38.80% | 2 | 7 | 2 | 6 | I H2H O AI | |||
| Kwiatkowski Thai-Son (USA) (578) | 61.20% | 1 | 6 (5) | 6 | 4 | ||||||
| Jul 10, 2017 17:05 |
negyeddöntő | Rybakov Alex (USA) (703) | 46.96% | 2 | 6 | 6 | I H2H O AI | ||||
| Torpegaard Mikael (DEN) (320) | 53.04% | 0 | 4 | 3 | |||||||
| Jul 9, 2017 21:15 |
nyolcaddöntő | Farren Connor (USA) (860) | 61.99% | 2 | 4 | 6 | 6 | I H2H O AI | |||
| Verryth Mark (AUS) (1775) | 38.01% | 1 | 6 | 2 | 4 | ||||||
| Jul 9, 2017 19:40 |
nyolcaddöntő | Bambridge Luke (GBR) (602) | 61.85% | 2 | 6 | 6 | I H2H O AI | ||||
| Kylar Kevin (CAN) (2051) | 38.15% | 0 | 3 | 1 | |||||||
| Jul 9, 2017 20:05 |
nyolcaddöntő | Martinez Luis David (VEN) (1046) | 38.69% | 2 | 7 | 6 | I H2H O AI | ||||
| Harris Andrew (AUS) (880) | 61.31% | 0 | 6 (4) | 2 | |||||||
| Jul 9, 2017 19:30 |
nyolcaddöntő | Peck Joshua (CAN) (1534) | 38.82% | 2 | 7 | 7 | I H2H O AI | ||||
| Tokuda Renta (JPN) (599) | 61.18% | 0 | 5 | 5 | |||||||
| Jul 9, 2017 17:10 |
nyolcaddöntő | Schneider Ronnie (USA) (1786) | 37.10% | 2 | 6 | 7 | I H2H O AI | ||||
| Bar Dekel (ISR) (620) | 62.90% | 0 | 2 | 6 (1) | |||||||
| Jul 9, 2017 17:10 |
nyolcaddöntő | Kwiatkowski Thai-Son (USA) (578) | 59.70% | 2 | 6 | 6 | I H2H O AI | ||||
| Leduc Antoine (CAN) (2011) | 40.30% | 0 | 1 | 2 | |||||||
| Jul 9, 2017 18:55 |
nyolcaddöntő | Rybakov Alex (USA) (703) | 42.96% | 2 | 6 | 6 | I H2H O AI | ||||
| O'Hare David (IRL) (2016) | 57.04% | 0 | 2 | 4 | |||||||
| Jul 9, 2017 18:20 |
nyolcaddöntő | Torpegaard Mikael (DEN) (320) | 48.29% | 2 | 6 | 6 | I H2H O AI | ||||
| Nicholls Shane (CAN) | 51.71% | 0 | 0 | 0 | |||||||
| Jul 9, 2017 17:00 |
1. kör | Verryth Mark (AUS) (1775) | 47.83% | 2 | 7 | 4 | 7 | I H2H O AI | |||
| Krainik Pavel (CAN) (956) | 52.17% | 1 | 5 | 6 | 5 | ||||||