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Bobusic Strahinja (1553) / Australia Hindle Zeke (1754) / USA
Strahinja Bobusic
castigate: 1
pierdute: 0
procentaj: 100 %
Zeke Hindle
castigate: 0
pierdute: 1
procentaj: 0 %
Bobusic Strahinja (1553) / Australia vs. Hindle Zeke (1754) / USA
Jun 7, 2008
00:00
1. runda Bobusic Strahinja (Aus.) 2 6 6 Loomis hard I
Hindle Zeke (USA) 0 4 2