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Robertson Scott (1918) / Australia Ramirez Rodriguez Hector / Mexico
Scott Robertson
wins: 2
losses: 0
percentage: 100 %
Hector Ramirez Rodriguez
wins: 0
losses: 2
percentage: 0 %
Robertson Scott (1918) / Australia vs. Ramirez Rodriguez Hector / Mexico
May 15, 2011
00:00
2. Round Robertson Scott (Aus.) 2 2 6 6 Mexico City hard I
Ramirez Rodriguez Hector (Mex.) 1 6 3 4
Nov 9, 2010
00:00
1. Round Robertson Scott (Aus.) [LL] 2 6 6 Durango hard I
Ramirez Rodriguez Hector (Mex.) 0 3 3